What useful work is performed by the engine, if the working fluid receives 200 kJ of heat from
| September 23, 2021 | education
What useful work is performed by the engine, if the working fluid receives 200 kJ of heat from the heater, the efficiency of the engine is 25%?
Q = 200 kJ = 200 * 10 ^ 3 J.
Efficiency = 25%.
Apol -?
According to the definition, efficiency is determined by the formula: efficiency = Apol * 100% / Azat, where Apol is useful work, Azat is work spent.
Since the body receives heat Q, then Azat is equal to the amount of heat that the body received.
Q = Azat.
Efficiency = Apol * 100% / Q.
Apol = efficiency * Q / 100%.
Apol = 25% * 200 * 10 ^ 3 J / 100% = 50 * 10 ^ 3 J.
Answer: useful work Apol = 50 * 10 ^ 3 J.
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