What V co2 is emitted when burning in 25 g of benzene?

The oxidation reaction of benzene is described by the following chemical reaction equation.

2C6H6 + 15O2 = 12CO2 + 6H2O;

According to the coefficients of this equation, 15 oxygen molecules are required to oxidize 2 benzene molecules. In this case, 12 molecules of carbon dioxide and 6 molecules of water are synthesized.

Let’s calculate the amount of benzene that has reacted.

To do this, divide its weight by the weight of 1 mole of benzene.

M C6H6 = 12 x 6 + 6 = 78 grams / mol;

N C6H6 = 25/78 = 0.321 mol;

The amount and volume of synthesized carbon dioxide will be:

N CO2 = 0.321 x 12/2 = 1.926 mol;

V CO2 = 1.926 x 22.4 = 43.142 liters;