What v (H2) is released in the interaction of 150 g of a 12% ethanol solution with metallic sodium?

We compose the reaction equation and arrange the coefficients:
2C2H5OH + 2Na = 2C2H5ONa + H2.
we calculate the amount of a substance in an ethanol solution. Formula: W = (mr.v – wa / mr – pa) / 100%
Calculation: 12 = (mr.v – wa / 150) * 100.
mr.v – wa = 18g.
the amount of ethanol substance: 18 / (12 * 2 + 1 * 5 + 16 + 1) = 18/46 = 0.39 mol.
from the amount of ethanol, we calculate the amount of the substance of the desired substance: n (H2) = 0.195 mol.
the volume of released hydrogen is found by the formula: V = Vm * n = 22.4 * 0.195 = 4.368 liters.
thus the volume of released hydrogen is 4.368 l