What voltage must be applied to a lead wire 2 m long so that the current in the wire differs by 2 A?

What voltage must be applied to a lead wire 2 m long so that the current in the wire differs by 2 A? Wire cross-sectional area 0.3mm

Given:

l = 2 meters – the length of the lead wire;

s = 0.3 mm2 is the specific sectional area of the lead wire;

r = 0.2 Ohm * mm2 / m – lead resistivity;

I = 2 Amperes – the required current.

It is required to determine U (Volt) – what voltage needs to be applied to the lead wire so that the current strength is I.

Find the resistance of the lead wire:

R = r * l / s = 0.2 * 2 / 0.3 = 0.4 / 0.3 = 1.3 Ohm (the result is rounded to one decimal place).

Then the voltage will be equal (Ohm’s law):

U = I * R = 2 * 1.3 = 2.6 Volts.

Answer: a voltage of 2.6 volts must be applied to the wire.