What voltage must be applied to an aluminum wire 2m long so that the current in it is 2A?

What voltage must be applied to an aluminum wire 2m long so that the current in it is 2A? Cross-sectional area of wire 0.2mm²

l = 2 m.
I = 2 A.

S = 0.2 mm2.

ρ = 0.028 Ohm * mm2 / m.

U -?

Ohm’s law for a section of a chain: U = I * R.

We express the resistance of an aluminum conductor by the formula: R = ρ * l / S, where ρ is the resistivity of aluminum, l is the length of the wire, S is the cross-sectional area of the wire.

U = I * ρ * l / S.

U = 2 A * 0.028 Ohm * mm2 / m * 2 m / 0.2 mm2 = 0.56 V.

Answer: voltage U = 0.56 V must be applied to the aluminum wire.