# What voltage should be applied to a nickelin conductor with a length of l = 2 mi with a cross-sectional area S = 0.5

**What voltage should be applied to a nickelin conductor with a length of l = 2 mi with a cross-sectional area S = 0.5 mm in order to create a current in it with a force of l = 5 A.**

Given:

l = 2 meters – the length of the nickeline conductor;

s = 0.55 mm2 – conductor cross-sectional area;

I = 5 Amperes – required current strength;

r = 0.4 Ohm * mm2 / m is the specific resistance of nickelin.

It is required to determine U (Volt) – what voltage must be applied to the conductor in order to create a current with a force I.

Find the resistance of the nickel conductor:

R = r * l / s = 0.4 * 2 / 0.55 = 0.8 / 0.55 = 1.45 Ohm (the result has been rounded to one hundredth).

Then the voltage will be equal to (Ohm’s law):

U = I * R = 5 * 1.45 = 7.25 Volts.

Answer: you need to apply a voltage equal to 7.25 volts.