What volume, amount of substance, number of particles is contained in 176 g of carbon dioxide.

univerkov | December 8, 2020 | education

N = m / M
n (CO2) = 176/44 = 4 mol – amount of substance
V = n * Vm
V (CO2) = 4 * 22.4 = 89.6 l – volume
N = n * NA
N = 4 * 6 * 10 ^ 23 = 24 * 10 ^ 23 pcs. – number of particles

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