What volume and mass of gas is formed by the interaction of a solution of sulfuric acid weighing 300 g

What volume and mass of gas is formed by the interaction of a solution of sulfuric acid weighing 300 g with a mass fraction of acid 0.294 with nastrium carbonate.

Given:
m (H2SO4) = 300 g
w% (H2SO4) = 29.4%
To find:
m (CO2) -?
V (CO2) -?
Decision:
H2SO4 + K2CO3 = K2SO4 + CO2 + H2O, – we solve the problem, relying on the composed reaction equation:
1) Find the mass of sulfuric acid in solution:
m (H2SO4) = 300 g * 0.294 = 88.2 g
2) Find the amount of sulfuric acid:
n (H2SO4) = m: M = 88.2 g: 98 g / mol = 0.9 mol.
3) We compose a logical expression:
if 1 mol H2SO4 gives 1 mol CO2,
then 0.9 mol H2SO4 will give x mol CO2,
then x = 0.9 mol.
4) Find the mass of carbon dioxide released during the reaction:
m (CO2) = n * M = 0.9 mol * 44 g / mol = 39.6 g.
5) Find the volume of carbon dioxide:
V (CO2) = n * Vm = 0.9 mol * 22.4 l / mol = 20.16 l.
Answer: m (CO2) = 39.6 g; V (CO2) = 20.16 l.