What volume does 3 g of gas take if the speed of its molecules is 0 5 km / s and they produce a pressure of 5 * 10 ^ 5 Pa.

m-gas mass
m = m0 * N = m0 * n * Na, where n is nu, amount of substance
Ek = m0 * U2 / 2 = 3 / 2kT = 3/2 (kpV / nR)
m0 = m / (n * Na)
m / Na * U2 = 3kpV / R
V = mRU2 / 3Nakp = mU2 / 3p
V = 0.003g * 250000m2 / s2 / 3 * 5 * 10 ^ 5 Pa = 50 * 10 ^ -5 m3
Answer V = 50 * 10 ^ -5 m3



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