What volume does argon take at -5 ° C and a pressure of 18 * 10 ^ 6 Pa, and its mass is 16 grams?

univerkov | June 10, 2021 | education

Initial data: Т (absolute temperature of argon) = -5 ºС = -5 + 273 = 268 К; P (argon pressure) = 18 * 10 ^ 6 Pa; m (mass of argon) = 16 g.

Reference values: M (molar mass, argon is an inert monoatomic gas) ≈ 40 g / mol; R (universal gas constant) = 8.31 J / (mol * K)).

The volume occupied by argon can be determined from the Mendeleev-Clapeyron equation: P * V = (m / M) * R * T.

V = (m / M) * R * T / P = (16/40) * 8.31 * 268 / (18 * 10 ^ 6) = 49.49 * 10 ^ -6 m ^ 3 = 49.49 cm ^ 3.

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