What volume is occupied by 6 mol of O2, 2 kmol of H2 and 1.5 Mmole of N2?
| September 30, 2021 | education
1. Let’s convert all values into moles:
2 Kmol = 2 * 103 mol.
1.5 mmol = 15 * 105 mol.
2. Let’s find the volumes of substances (Vm – molar volume, constant equal to 22.4 l / mol):
V (O2) = n (O2) * Vm = 6 mol * 22.4 L / mol = 134.4 L.
V (H2) = n (H2) * Vm = 2 * 103 mol * 22.4 L / mol = 44800 L.
V (N2) = n (N2) * Vm = 15 * 105 mol * 22.4 l / mol = 33,600,000 l.
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