What volume is occupied by: a) 0.2 mol of oxygen; b) 88 g of carbon monoxide (IV)

What volume is occupied by: a) 0.2 mol of oxygen; b) 88 g of carbon monoxide (IV) What volume is occupied by: a) 64 g of oxygen; b) 0.5 mol sulfur (IV) oxides

The volume is found by the formula: V = n * Vm, where n is the amount of substance, mol; Vm = 22.4 l / mol – molar volume constant for all gases at n. at. a) V (O2) = 0.2 mol * 22.4 L / mol = 4.48 L. b) Find the amount of CO2 n = m / M, where the molar mass (according to the periodic table) M = 12 + 16 * 2 = 44 g / mol. n (CO2) = 88 g / 44 g / mol = 2 mol. Then the volume V (CO2) = n * Vm = 2 mol * 22.4 l / mol = 44.8 l. a) n (O2) = 64 g / 32 g / mol = 2 mol. V (O2) = 2 mol * 22.4 L / mol = 44.8 L. b) V (SO2) = 0.5 mol * 22.4 l / mol = 11.2 l.