What volume is occupied under normal conditions: a) 5 g of oxygen, b) 0.3 mol of sulfur (IV) oxide

univerkov | May 27, 2021 | education

What volume is occupied under normal conditions: a) 5 g of oxygen, b) 0.3 mol of sulfur (IV) oxide, c) a mixture consisting of 0.3 mol of nitrogen and 11 g of carbon dioxide?

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

n = m: M.

А). M (O2) = 32 g / mol.

n = 5 g: 32 g / mol = 0.156 mol.

V = 22.4 L / mol × 0.156 = 3.49 L.

B). V (SO2) = 0.3 mol × 22.4 L / mol = 6.72 L.

С) V (N2) = 22.4 L / mol × 0.3 mol = 6.72 L.

M (CO2) = 44 g / mol.

n = 11g: 44 g / mol = 0.25 mol.

V = 22.4 L / mol × 0.25 mol = 5.6 L.

V (mixture) = 5.6 l + 6.72 l = 12.32 l.

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