What volume is required for complete combustion of 6.72lit methane?

The methane oxidation reaction is described by the following chemical reaction equation.
CH4 + 2O2 = CO2 + 2H2O;
In accordance with the coefficients of this equation, for the oxidation of 1 molecule of methane, 2 molecules of oxygen are required. This synthesizes 1 molecule of carbon dioxide.
The molar volume of the gas is standard and under normal conditions it fills a volume of 22.4 liters.
Since the molar volume of the gas is standard, twice the amount of oxygen will require twice the volume.
The required volume of oxygen will be 6.72 x 2 = 13.44 liters.

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