What volume of 20% hydrochloric acid (density = 1.134 g / mol) will be required to prepare 1 liter. 3n. solution?

1. Calculate the equivalent chemical amount of hydrochloric acid:

neq (HCl) = CH (HCl) * V (HCl solution);

neq (HCl) = 3 * 1 = 3 mol eq;

2. find the mass of hydrogen chloride:

m (HCl) = neq (HCl) * M (HCl) = 3 * 36.5 = 109.5 g;

3.Calculate the mass of the HCl solution:

m (solution) = m (HCl): w (HCl) = 109.5: 0.2 = 547.5 g;

4.determine the volume of acid:

V (HCl solution) = m (solution): ρ = 547.5: 1.134 = 482.8 ml.

Answer: 482.8 ml.