What volume of acetylene can be obtained from 80 g of calcium carbide CaC2 Ar (Ca) = 40 Ar (C) = 12.

The reaction for the synthesis of acetylene from calcium carbide is described by the following chemical reaction equation:

CaC2 + 2H2O = C2H2 + Ca (OH) 2;

From 1 mole of calcium carbide, 1 mole of acetylene is synthesized.

Let’s calculate the available chemical amount of silicon carbide substance.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

N CaC2 = 80/64 = 1.25 mol;

The same molar amount of gaseous acetylene will be synthesized.

Let’s define its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of gaseous substance (22.4 liters).

V C2H2 = 1.25 x 22.4 = 28 liters;