What volume of acetylene is required to obtain ethanal weighing 88 g?

Decision:
1) We compose the reaction equation corresponding to the condition of the problem:
C2H2 + H2O = CH3CHO;
2) Find the amount of ethanal contained in 88 grams of the substance:
n (CH3CHO) = m: M = 88 g: 44 g / mol = 2 mol;
3) We compose a logical expression:
if 1 mol of C2H2 gives 1 mol of CH3CHO,
then 2 mol C2H2 will give x mol CH3CHO,
then x = 2 mol.
4) Find the volume of acetylene required for the reaction to proceed:
V (C2H2) = n * Vm = 2 mol * 22.4 L / mol = 44.8 L.
Answer: V (C2H2) = 44.8 liters.