# What volume of acid with a density of 1.8 g / ml with a concentration of 88% should

What volume of acid with a density of 1.8 g / ml with a concentration of 88% should be taken to prepare 300 ml of 40% with a density of 1.3 g / ml.

Given:
ρ1 solution (acid) = 1.8 g / ml
ω1 (acid) = 88%
V2 solution (acid) = 300 ml
ω2 (acid) = 40%
ρ2 solution (acid) = 1.3 g / ml

Find:
V1 solution (acid) -?

1) m2 solution (acid) = ρ2 solution * V2 solution = 1.3 * 300 = 390 g;
2) m2 (acid) = ω2 * m2 solution / 100% = 40% * 390/100% = 156 g;
3) m1 (acid) = m2 (acid) = 156 g;
4) m1 solution (acid) = m1 * 100% / ω1 = 156 * 100% / 88% = 177.27 g;
5) V1 solution (acid) = m1 solution / ρ1 solution = 177.27 / 1.8 = 98.5 ml.

Answer: The volume of the acid solution is 98.5 ml.

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