What volume of air, which contains 21% oxygen per volume, will be spent on burning ethane with a mass of 240 g?

univerkov | September 8, 2021 | education

Reaction equation: 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O.

The molar mass of ethane M (C2H6) = 12 × 2 + 1 × 6 = 30 g / mol.

Ethane amount: n = m / M = 240/30 = 8 mol.

The ratio of the amount of ethane to the amount of oxygen: 2: 7.

Find the amount of oxygen (x). 2: 7 = 8: x. x = 7 × 8: 2 = 28 mol.

Let’s calculate the volume of oxygen V (O2) = n × Vm = 28 × 22, 4 = 627, 2 liters.

Let’s calculate the volume of air V (air) = 627.2 × 100%: 21% = 2986.67 liters.

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