What volume of alcohol will heat up by 10 degrees when transferring 0.2 MJ of energy to it?

Initial data: Δt (change in alcohol temperature) = 10 ºС; Q (the amount of energy that was transferred to the alcohol) = 0.2 MJ = 0.2 * 10 ^ 6 J.
Reference data: ρ (density of alcohol) = 800 kg / m ^ 3; C (specific heat of alcohol) = 2500 J / (kg * K).
1) Calculate the mass of heated alcohol: Q = C * m * Δt and m = Q / (C * Δt) = 0.2 * 10 ^ 6 / (2500 * 10) = 8 kg.
2) Determine the volume of alcohol: V = m / ρ = 8/800 = 0.01 m ^ 3.
Answer: 0.01 m ^ 3 of alcohol will heat up.