What volume of ammonia can be obtained from 10.7 g of ammonium chloride if the yield

What volume of ammonia can be obtained from 10.7 g of ammonium chloride if the yield of ammonia is 80% of the theoretical possible?

To solve it, you need to make an equation:
NH4Cl + NaOH = NH3 + NaCl + H2O – ion exchange, ammonia is released;
Let’s calculate the molar masses of substances:
M (NH4Cl) = 53.5 g / mol;
M (NH3) = 17 g / mol.
Determine the number of moles of ammonium chloride salt:
Y (NH4Cl) = m / M = 10.7 / 53.5 = 0.2 mol;
In writing the equation, the amount of moles of ammonium chloride salt and gaseous ammonia are equal to 1 mole, which means that Y (NH3) = 0.2 mole.
Find the volume of ammonia:
V (NH3) = 0.2 * 22.4 = 4.48 l.
Answer: the volume of ammonia is 4.48 liters.