What volume of ammonia can be obtained from 280 g of nitrogen if the reaction yield = 10%?

Given:

m (N2) = 280 g;

w% (NH3 practical) = 10%;

To find:

V (NH3) -?

Decision:

1) We compose the reaction equation corresponding to the condition of the problem:

N2 + 3H2 = 2NH3;

2) Find the amount of nitrogen contained in 280 grams of gas:

n (N2) = m: M = 280 g: 28 g / mol = 10 mol;

3) We compose logical equality:

if 1 mol of N2 gives 2 mol of NH3,

then 10 mol of N2 will give x mol of NH3,

then x = 20 mol.

4) Find the theoretical volume of ammonia output:

V (NH3) = n * Vm = 20 mol * 22.4 L / mol = 448 L;

5) Find the actual product yield:

V (NH3) = 448 L * 0.1 = 44.8 L;

Answer: V (NH3) = 44.8 liters.