What volume of ammonia is formed by the interaction of 67.2 liters of nitrogen and 224 liters of hydrogen?

The reaction for producing ammonia is described by the following chemical reaction equation:

N2 + 3H2 = 2NH3;

The nitrogen molecule has two nitrogen atoms, and the ammonia molecule has one nitrogen atom. Therefore, from one mole of nitrogen, two moles of ammonia can be obtained.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Therefore, from 67.2 liters of nitrogen, 134.4 liters of ammonia can be obtained.

Determine the required volume of hydrogen.

A hydrogen molecule has two hydrogen atoms, and an ammonia molecule has three hydrogen atoms. Therefore, from one mole of hydrogen, you can get 2/3 mole of ammonia.

Therefore, the reaction will require 134.4 x 3/2 = 201.6 liters of hydrogen.

There is enough hydrogen to produce 134.4 liters of ammonia from 64.2 liters of nitrogen.