What volume of ammonia is formed when heating a mixture consisting of 20 g of ammonium chloride and 20 g of calcium hydroxide.

univerkov | November 16, 2020 | education

We write down the equation of reactions.
2NH4Cl + Ca (OH) 2 = CaCl2 + 2NH3 + 2 H2O.
Next, we find the amount of the substance of ammonium chloride and sodium hydroxide.
n = m / M.
M (NH4Cl) = 54.48.
n = 20 / 54.48 = 0.37 mol.
M (Ca (OH) = 74 g / mol.
n (Ca (OH)) = 20/74 = 0.27 mol.
Since about calcium dioxide is in excess, we count by ammonium chloride, we find the amount of ammonia substance.
0.37 mol NH4Cl – x mol NH3.
2 mol NH4Cl – 2 mol NH3.
X = 2 * 0.37: 2 = 0.34 mol NH3.
Find the volume of ammonia.
V = n * Vm = 0.34 * 22.4 = 0.68 liters.
Answer: V (NH3) = 0.68 L.

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