What volume of ammonia is obtained by the action of alkali on ammonium sulfate weighing 33 g.

Determine the chemical amount of ammonium sulfate. To do this, we divide its weight by its molar mass.

For this purpose, we divide the weight of the substance by its molar (atomic) mass.

M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;

The amount of ammonium sulfate will be:

N (NH4) 2SO4 = 33/132 = 0.25 mol;

When decomposing such an amount of salt, you can get 0.25 x 2 = 0.5 mol of ammonia.

Let’s calculate its volume.

To do this, multiply the amount of substance by the standard volume of 1 mole of gas (filling 22.40 liters)

V NH3 = 0.5 x 22.4 = 11.2 liters;