What volume of ammonia must be taken to obtain ammonium chloride with a mass of 5.25 g?

1. Let’s write down the reaction equation:

NH3 + HCl = NH4Cl.

2. Find the amount of ammonium chloride:

n (NH4Cl) = m (NH4Cl) / M (NH4Cl) = 5.25 g / 53.5 g / mol = 0.098 mol.

3. According to the reaction equation, we find the amount of ammonia, and then its volume (Vm is the molar volume, constant equal to 22.4 l / mol):

n (NH3) = n (NH4Cl) = 0.098 mol.

V (NH3) = n (NH3) * Vm = 0.098 mol * 22.4 L / mol = 2.2 L.

Answer: V (NH3) = 2.2 liters.