What volume of ammonia NH3 is formed during the decomposition of 270 g of ammonium

What volume of ammonia NH3 is formed during the decomposition of 270 g of ammonium chloride containing 20% of impurities?

The decomposition reaction of ammonium chloride is described by the following chemical reaction equation:

NH4Cl = NH3 + HCl;

In this reaction, from one mole of ammonium chloride, one mole of ammonia and one mole of hydrochloric acid are formed.

Let’s find the available quantities of the substance.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

N NH4Cl = 270 / 53.5 x 0.8 = 4.037 mol;

During the reaction, 4.037 mol of ammonia will be obtained. Let’s define its volume.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

V NH3 = 4.037 x 22.4 = 90.43 liters;