What volume of ammonia will be obtained by the interaction of 80 g of sodium hydroxide with ammonium nitrate?

Let’s carry out the solution, write down the equation according to the condition of the problem:
NaOH + NH4NO3 = NaNO3 + NH3 + H2O – ion exchange reaction, ammonia is released;
Let’s calculate the molar mass of sodium hydroxide:
M (NaOH) = 39.9 g / mol.
Let us determine the number of moles of NaOH base if the mass is known:
Y (NaOH) = m / M = 80 / 39.9 = 2 mol;
According to the equation, the amount of moles of the base NaOH and ammonia NH3 are equal to 1 mol, which means that Y (NH3) = 2 mol.
Find the volume of ammonia by applying Avogadro’s law:
V (NH3) = 2 * 22.4 = 44.8 liters.
Answer: the volume of ammonia is 44.8 liters.