What volume of an aluminum bar should be taken so that the force of gravity acting on it near

What volume of an aluminum bar should be taken so that the force of gravity acting on it near the surface of the earth was equal to 270N?

Initial data: Fт (gravity, which should act on an aluminum bar) = 270 N.

Reference data: according to the condition ρа (aluminum density) = 2700 kg / m3; g (acceleration due to gravity) = 10 m / s2.

1) Determine the mass of the aluminum bar: m = Ft / g = 270/10 = 27 kg.

2) Let’s calculate the required volume of an aluminum bar: V = m / ρа = 27/2700 = 0.01 m3.

Answer: It is necessary to take an aluminum bar with a volume of 0.01 m3.