What volume of an aluminum block should be taken so that the force of gravity acting on it near

What volume of an aluminum block should be taken so that the force of gravity acting on it near the surface of the earth was equal to 270N?

Given:
F = 270 Newton – gravity acting on an aluminum bar near the Earth’s surface;
g = 10 N / kg – acceleration of gravity;
ro = 2700 kg / m ^ 3 is the density of aluminum.
It is required to determine the volume of aluminum V (cubic meter).
Let’s find the mass of aluminum:
m = F / g = 270/10 = 27 kilograms.
Then the volume of aluminum will be equal to:
V = m / ro = 27/2700 = 0.01 cubic meter.
Answer: the volume of an aluminum bar will be 0.01 cubic meters.