What volume of benzene (density 0.88 g / ml) can be obtained by two-stage synthesis from

What volume of benzene (density 0.88 g / ml) can be obtained by two-stage synthesis from 71.1 kg of technical calcium carbide containing 10% of impurities, if the product yield in the first stage of the process is 90% in the second 45?

Acetylene is synthesized by the interaction of calcium carbide with water.

CaC2 + 2H2O = Ca (OH) 2 + C2H2 ↑;

Let’s determine the molar amount of calcium carbide.

To do this, add up the molar weights of the elements that make up this molecule.

M CaC2 = 40 + 12 x 2 = 64 grams / mol;

N CaC2 = 71 100 x 0.9 / 64 = 1000 mol;

Theoretically, the same amount of acetylene will be synthesized.

From this amount of acetylene, 3 times less benzene can be synthesized.

Let’s find its weight:

M C6H6 = 12 x 6 + 6 = 78 grams / mol;

m C6H6 = 1000/3 x 78 = 26,000 grams;

Taking into account the reaction yield at 1 stage 90% and at the second 45%, the weight of benzene will be:

m C6H6 = 26,000 x 0.9 x 0.45 = 10,530 grams;