What volume of carbon (4) oxide can be obtained by decomposition of 26 g of barium carbonate containing 4% impurities?

The decomposition reaction of barium carbonate when heated is described by the following chemical equation:

BaCO3 = BaO + CO2 ↑;

Find the chemical amount of barium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M BaCO3 = 137 + 12 + 16 x 3 = 197 grams / mol;

N BaCO3 = 26 x 0.96 / 197 = 0.1267 mol;

The same molar amount of carbon dioxide can theoretically be obtained.

In order to calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (taking a volume of 22.4 liters).

V CO2 = 0.1267 x 22.4 = 2.838 liters;