What volume of carbon dioxide can be obtained by the interaction of oxygen with 20 g of carbon dioxide containing 10%.

Given:
m mixture (C) = 20 g
w approx (C) = 10%
To find:
V (CO2)
Decision:
C + O2 = CO2
w clean water (C) = 100% -10% = 90% = 0.9
m in-va (C) = w pure in-va * m mixture = 0.9 * 20 g = 18 g
n (C) = m / M = 18 g / 12 g / mol = 1.5 mol
n (C): n (CO2) = 1: 1
n (CO2) = 1.5 mol
V (CO2) = n * Vm = 1.5 mol * 22.4 l / mol = 33.6 l
Answer: 33.6 L