What volume of carbon dioxide CO2 will be released during the burning of CaCO3 with a mass of 1 kg

What volume of carbon dioxide CO2 will be released during the burning of CaCO3 with a mass of 1 kg and a mass fraction of impurities of 15%

The thermal decomposition of calcium carbonate.
CaCO3 = CaO + CO2.
Let’s find the mass of impurities in the carbonate.
m (approx.) = 1000 g • 15% / 100% = 150 g.
The mass of the pure substance, including impurities.
m (CaCO3) = 1000 g – 150 g = 850 g.
The amount of moles of carbonate and carbon dioxide will be equal.
n (CaCO3) = n (CO2) = m / Mr = 850 g / 100 g / mol = 8.5 mol.
The volume of the generated gas.
V (CO2) = n • Vm = 8.5 mol • 22.4 mol / L = 190.4 L.