What volume of carbon dioxide is formed by the reaction of 73 g of hydrochloric acid with sodium carbonate?

Let’s complete the task:
1. Let’s write down the reaction equation:
2HCl + Na2CO3 = 2NaCl + CO2 + H2O – ion exchange reaction, carbon dioxide is released;
2. Determine the molar mass of HCl: M (HCl) = 36.5 g / mol.
3. Let’s calculate the number of moles of hydrochloric acid, if the mass is known: m (HCl) = 73 g
Y (HCl) = m (HCl) / M (HCl); Y (HCl) = 73 / 36.5 = 2 mol;
4. Let’s make a proportion according to the reaction equation data:
2 mol (HCl) -X mol (CO2);
-2 mol – 1 mol from here, X mol (CO2) = 2 * 1/2 = 1 mol;
5. According to Avogadro’s law, 1 mole of any gas at n. y takes V = 22.4 liters.
V (CO2) = 22.4 liters.
Answer: during the reaction, carbon dioxide is released in a volume of 22.4 liters.