What volume of carbon dioxide is formed during the oxidation of 1.5 mol of glucose?

If we are talking about the carbon dioxide of the newspaper, then oxidation is understood as combustion. Let’s write down the reaction equation and arrange the coefficients: С6Н12О6 + 6О2 -> 6СО2 + 6Н2О. Carbon dioxide is 6 times more than 1.5 * 6 * 22.4 = 201.6 liters.



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