What volume of carbon dioxide is formed from 400 g of limestone (calcium carbonate) containing 25% impurities?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

When decomposing 1 mol of limestone, 1 mol of calcium oxide and 1 mol of carbon monoxide is obtained.

Let’s calculate the chemical amount of calcium carbonate. For this purpose, we divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 400 x 0.75 / 100 = 3 mol;

Find the volume of 3 moles of carbon dioxide.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 3 x 22.4 = 67.2 liters;