What volume of carbon dioxide is formed when 200 g of 4.9% sulfuric acid act on an excess of calcium carbonate?

The reaction of dissolution of calcium carbonate in sulfuric acid is described by the following chemical reaction equation:

CaCO3 + H2SO4 = CaSO4 + CO2 + H2O;

When 1 mol of calcium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 1 mol of sulfuric acid. In this case, calcium sulfate is synthesized.

Let’s calculate the available chemical amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 200 x 0.049 / 98 = 0.1 mol;

Thus, when 0.1 mol of chalk is dissolved, 0.1 mol of carbon dioxide is synthesized.

This will consume 0.1 mol of acid. Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.1 x 22.4 = 2.24 liters;