What volume of carbon dioxide is produced by dissolving 250 grams of limestone (potassium carbonate

What volume of carbon dioxide is produced by dissolving 250 grams of limestone (potassium carbonate containing 20% impurities) with the required amount of nitric acid? How much is this?

The reaction of interaction of limestone with nitric acid is described by the following chemical reaction equation:

CaCO3 + 2HNO3 = Ca (NO3) 2 + H2O + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 250 x (1 – 0.2) / 100 = 2 mol;

During the reaction, the same amount of carbon dioxide will be synthesized.

For these purposes, you will need 2 x 2 = 4 mol of nitric acid.

Let’s calculate its volume.

To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 4 x 22.4 = 89.6 liters;