What volume of carbon dioxide is released when 5 g of soda (Na2CO3) interacts with hydrochloric acid?

Reaction equation: Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
Let’s find the amount of soda substance n = m / M = 5 g / 106 g / mol = 0.047 mol. (M – molar mass, determined by the periodic table). According to the reaction from 1 mole of soda, 1 mole of carbon dioxide is obtained, that is, n (Na2CO3) = n (CO2) = 0.047 mol. Then we find the volume of gas V = n * Vm = 0.047 mol * 22.4 L / mol = 1.0528 L. (Vm – molar volume, constant for all gases under normal conditions).
Answer: the volume of carbon dioxide is 1.0528 liters.