What volume of carbon dioxide is released when 70 g of a solution with a mass fraction of 70%

What volume of carbon dioxide is released when 70 g of a solution with a mass fraction of 70% sulfuric acid on sodium carbonate?

1. Let’s write down the reaction equation:

Na2CO3 + H2SO4 = Na2SO4 + CO2 + H2O.

2. Find the amount of sulfuric acid:

m (H2SO4) = (m (solution) * ω (H2SO4)) / 100% = 70 g * 70% / 100% = 49 g.

n (H2SO4) = m (H2SO4) / M (H2SO4) 49 g / 98 g / mol = 0.5 mol.

3. according to the reaction equation, we find the amount of carbon dioxide, and then its volume (Vm is the molar volume, constant equal to 22.4 l / mol):

n (CO2) = n (H2SO4) = 0.5 mol.

V (CO2) = n (CO2) * Vm = 0.5 mol * 22.4 L / mol = 11.2 L.

Answer: V (CO2) = 11.2 liters.