What volume of carbon dioxide was obtained from the decomposition of 50 g of calcium carbonate

What volume of carbon dioxide was obtained from the decomposition of 50 g of calcium carbonate if the reaction of the product is 75%?

The thermal decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2 ↑;

Let’s calculate the chemical amount of calcium carbonate (limestone). To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 50/100 = 0.5 mol;

Taking into account the reaction yield of 75%, 0.5 x 0.75 = 0.375 mol of carbon dioxide will be synthesized.

To find its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V CO2 = 0.375 x 22.4 = 8.4 liters;