What volume of carbon dioxide was passed through the limestone if the reaction resulted in a precipitate weighing 10 g?

1. Let’s compose the equation of the reaction that occurs when carbon dioxide is passed through lime water:

CO2 + Ca (OH) 2 = CaCO3 ↓ + H2O;

2.determine the chemical amount of calcium carbonate:

n (CaCO3) = m (CaCO3): M (CaCO3);

M (CaCO3) = 40 + 12 + 3 * 16 = 100 g / mol;

n (CaCO3) = 10: 100 = 0.1 mol;

3.According to the coefficients of the equation, we find the amount of carbon dioxide:

n (CO2) = n (CaCO3) = 0.1 mol;

V (CO2) = n (CO2) * Vm = 0.1 * 22.4 = 2.24 liters.

Answer: 2.24 liters.