What volume of carbon dioxide will be released during the combustion of 5.6 liters of ethane?

Given:

V1 (C2H6) = 5.6 liters.

To find:

V2 (CO2) =?

Solution:

1) We compose the equation of the chemical reaction:

2C2H6 + 7O2 = 4CO2 + 6H2O.

2) The formula for solving the problem: V1: Vm1 = V2: Vm2, hence V2 = (V1 x Vm2): Vm1.

3) Vm1 (C2H6) = 2 x 22.4 L / mol = 44.8 L / mol.

Vm2 (CO2) = 4 x 22.4 L / mol = 89.6 L / mol.

4) 5.6 L: 44.8 L / mol = V2: 89.6 L / mol,

V2 (CO2) = (5.6 x 89.6): 44.8 = 11.2 HP

Answer: V2 (CO2) = 11.2 liters.