What volume of carbon dioxide will be released during the combustion of 5 liters of propane with 20% impurities?

1) Calculate the volume of pure propane (80%): V (C3H8) = (5/100%) * 80% = 4 liters;
2) Calculate the number of moles of propane: Vm = 22.4 L at normal conditions, n (C3H8) = 4 / 22.4 = 0.179 mol;
3) Determine the amount of moles of carbon dioxide: n (CO2) = 3 * n (C3H8) = 3 * 0.179 = 0.536 mol;
4) Calculate the volume of carbon dioxide: V (CO2) = 0.536 * 22.4 = 12 liters;
Answer: 12 l