What volume of carbon dioxide will be released during the decomposition of 400 g of limestone containing 30% of impurities?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

The decomposition of 1 mole of limestone synthesizes 1 mole of calcium oxide and 1 mole of carbon monoxide. Let’s calculate the chemical amount of calcium carbonate. For this purpose, we divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 400 x 0.7 / 100 = 2.8 mol;

Let’s calculate the volume of 2.8 mol of carbon dioxide.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 2.8 x 22.4 = 62.72 liters;