What volume of carbon dioxide will be released if 200 g of 14.6% hydrochloric acid solution reacted with marble?

univerkov | November 21, 2020 | education

CaCO3 + 2HCl = H2O + CO2 + CaCl2
m (HCl) neat = 200g × 0.146 = 29.2g
n = 29.2 / 36.5 = 0.8 mol
n (CO2) = 0.8 / 2 = 0.4 mol
V (CO2) = nVm = 0.4 × 22.4 = 8.96 L

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