What volume of carbon dioxide will be released under the action of hydrochloric acid on 170 g

What volume of carbon dioxide will be released under the action of hydrochloric acid on 170 g of limestone containing 20% of impurities?

When calcium carbonate reacts with hydrochloric acid, calcium chloride, water and gaseous carbon dioxide are produced. The reaction is described by the following equation:

CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O;

Let’s determine the chemical amount of calcium carbonate. To do this, divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 170 x 0.8 / 100 = 1.36 mol;

1.36 mol of calcium carbonate will react with 1.36 x 2 = 2.72 mol of hydrochloric acid. This will release 1.36 mol of carbon dioxide.

Let’s calculate the volume that it occupies. To this end, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 1.36 x 22.4 = 30.464 liters;