What volume of carbon dioxide will be released when 450 g of 30% nitric acid solution acts on calcium carbonate?

univerkov | July 17, 2021 | education

1. Let’s write down the reaction equation:

CaCO3 + 2HNO3 = Ca (NO3) 2 + CO2 + H2O.

2. Find the amount of nitric acid:

m (HNO3) = (m (solution) * ω (HNO3)) / 100% = 450 g * 30% / 100% = 135 g.

n (HNO3) = m (HNO3) / M (HNO3) = 135 g / 63 g / mol = 2.14 mol.

3. According to the reaction equation, we find the amount of carbon dioxide, and then its volume (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = 2n (HNO3) = 2 * 2.14 mol = 4.23 mol.

V (CO2) = n (CO2) * Vm = 4.23 mol * 22.4 l / mol = 96 l.

Answer: V (CO2) = 96 l.

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