What volume of carbon monoxide (4) can react with sodium hydroxide weighing 4 g?

To solve, we will compose the reaction equation, arrange the coefficients:
2NaOH + CO2 = Na2CO3 + H2O – exchange reaction, sodium carbonate and water are released;
M (NaOH) = 39.9 g / mol; M (CO2) = 44 g / mol;
Let’s calculate the number of moles of sodium hydroxide:
Y (NaOH) = m / M = 4 / 39.9 = 0.1 mol;
Let’s make the proportion:
0.1 mol (NaOH) – X mol (CO2);
-2 mol -1 mol hence, X mol (CO2) = 0.1 * 1/2 = 0.05 mol;
Find the volume of carbon monoxide:
V (CO2) = 0.05 * 22.4 = 1.2 l.
Answer: carbon monoxide with a volume of 1.12 liters is involved in the reaction.